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.048-2000x+250000x^2=0
We add all the numbers together, and all the variables
250000x^2-2000x+0.048=0
a = 250000; b = -2000; c = +0.048;
Δ = b2-4ac
Δ = -20002-4·250000·0.048
Δ = 3952000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3952000}=\sqrt{1600*2470}=\sqrt{1600}*\sqrt{2470}=40\sqrt{2470}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2000)-40\sqrt{2470}}{2*250000}=\frac{2000-40\sqrt{2470}}{500000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2000)+40\sqrt{2470}}{2*250000}=\frac{2000+40\sqrt{2470}}{500000} $
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